Factoring the time
current mood: beyond geeky
Posted by: metahacker (metahacker)
Posted at: April 11th, 2007 01:40 pm (UTC)

I don't factor the time, I find ways to insert operators to make a valid equation.
2=53 is easy
1=sqrt(4)/(53) is a bit harder
At one point I worked out what the potential equations are for every possible time. There are a number of intractable times, such as 9:37.
Posted by: Who, me? (metageek)
Posted at: April 11th, 2007 01:53 pm (UTC)
Arrgh 
I don't factor the time, I find ways to insert operators to make a valid equation.
Oh, great, now you've given me a new obsession to try out. ;)
There are a number of intractable times, such as 9:37.
Depends on your ring. In Z_{10}, 9=(3*7).
Posted by: metahacker (metahacker)
Posted at: April 11th, 2007 01:56 pm (UTC)
Re: Arrgh 
See, I'd allow that but only if you could find Z or 10 in the time...
Posted by: Who, me? (metageek)
Posted at: April 11th, 2007 02:30 pm (UTC)
Re: Arrgh 
Ah, but Z and 10 aren't digits; they won't be in the time, just like + and * won't be.
On the other hand, 9 in Z_{10} is not the same number as 9 in Z, so you could say that it's not in 9:37 either.
Posted by: metahacker (metahacker)
Posted at: April 11th, 2007 08:53 pm (UTC)
Re: Arrgh 
Hmm. Though you could argue the 9 is in Z_{12}...
Of course this comic reminded me of you this morning, but apparently it's worse than I thought.