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Who, me? [userpic]

Factoring the time

April 11th, 2007 (09:16 am)
current mood: beyond geeky

Today's xkcd:

Amateurs. When I factor the time (which I mostly manage to avoid these days...), the number I factor is the number of minutes from midnight. So 2:53 PM is 14*60+53=893=19*47.

Comments

Posted by: C. Virtue (cvirtue)
Posted at: April 11th, 2007 01:18 pm (UTC)
LotR pants

Of course this comic reminded me of you this morning, but apparently it's worse than I thought.

Posted by: metahacker (metahacker)
Posted at: April 11th, 2007 01:40 pm (UTC)
statistic

I don't factor the time, I find ways to insert operators to make a valid equation.

2=5-3 is easy
1=sqrt(4)/(5-3) is a bit harder

At one point I worked out what the potential equations are for every possible time. There are a number of intractable times, such as 9:37.

Posted by: Who, me? (metageek)
Posted at: April 11th, 2007 01:53 pm (UTC)
Arrgh

I don't factor the time, I find ways to insert operators to make a valid equation.

Oh, great, now you've given me a new obsession to try out. ;-)

There are a number of intractable times, such as 9:37.

Depends on your ring. In Z10, 9=-(3*7).

Posted by: metahacker (metahacker)
Posted at: April 11th, 2007 01:56 pm (UTC)
Re: Arrgh
miracle

See, I'd allow that but only if you could find Z or 10 in the time...

Posted by: Who, me? (metageek)
Posted at: April 11th, 2007 02:30 pm (UTC)
Re: Arrgh

Ah, but Z and 10 aren't digits; they won't be in the time, just like + and * won't be.

On the other hand, 9 in Z10 is not the same number as 9 in Z, so you could say that it's not in 9:37 either.

Posted by: metahacker (metahacker)
Posted at: April 11th, 2007 08:53 pm (UTC)
Re: Arrgh
feet

Hmm. Though you could argue the 9 is in Z12...

Posted by: Who, me? (metageek)
Posted at: April 11th, 2007 11:09 pm (UTC)
Re: Arrgh

Yeah, and the 37 is in Z60.

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